Samuel Halpern
Member
Very interesting analysis Georges.
Robert Duane Ballard, a US Navy officer and professor of oceanography at the University of Rhode Island, discovered in the early morning hours of September 1st,1985, the RMS TITANIC wreck. The most probable position where the liner sank was given as 41°43.5’N / 049°56.8’W. Titanic enthusiasts jumped on the occasion to compare the wreck position against Smith and Boxhall CQD’s. It was found that the former distress position was 20 nautical and the latter 13 miles, both further to the west. Boxhall 41°46’N / 050°14’W CQD is recognized to be the official distress position.
Since 1985, every enthusiast tried to explain how a 13 miles offset could have happened. However, deducing 13 miles offset from the CQD against the Wreck position is at the source an incorrect navigation and shiphandling principle. It is absolutely impossible that at the time of collision, the liner was brought dead stop in split seconds, in still ocean waters and iceberg right by her side so to rest at exact wreck position. At the time of collision, the vessel was further east and south due to set & drift meaning that the erroneous distance was even greater!
Everybody saw in the movie Smith rushing in the navigation bridge. After hearing what Murdoch had to say, he ordered to close the watertight doors and the engines all stop (which was already done in real life), then he ordered finding the carpenter to sound the vessel. There is something missing here; the captain should then have told the mate that he was taking over command. The mate would then have notified him that the engines were ordered all stop, the elm hard over to port, the vessel swinging to starboard and there was nothing in sight.
The captain would then make sure the berg was clear before ordering the elm amidship. Later, we have testimonies that the commodore clutched the engines astern and then ahead followed by stop for good. That was a very audacious for not saying a reckless maneuver to fiddle about the engines after hitting ice in open waters. A damaged or loosen propeller(s) blade(s) could have been propelled against the hull and or a shaft been misaligned making the stern tube via the stuffing box, to both ingress more water. At least, the engine settings were slow and for a short period of time to the extent that the liner drifted mostly dead on her own inertia for a minimum of 15 minutes.
In the very best conditions, a fully standing by engine crew would crash stop the lightship giant in over half a nautical mile while being beaten up by enormous vibrations. That never happened. Titanic colliding at 22½ knots was developing 2 billion ft/lbs kinetic energy! According to Samuel studies, the titan went from 38 ft/s (22½ knots) at elm amidship, to 35 ft/sec (20¾ knots) at elm hard over and then to 34.5 ft/sec (20½ knots) after impact.
In 2013, A New Method for Accurate Prediction of Ship’s Inertial Stopping Distance calculated by the ALE (Arbitrary Lagrangian Eulerian) algorithm was elaborated. When compared with shipbuilders’ experimental basin data, the results calculated by ALE algorithm reach a precision of 98% while the results calculated by Captain Topley empirical formula (1988) reach a relative precision of 90.4%. Here is the formula:
View attachment 48362
SJ = The inertial stopping distance
v1 = The ship’s speed at dead stop or dropping anchor
v0 = The ship’s initial speed at stopping
C = The time halved constant of ship’s speed and can be calculated or interpolated from Table 1.
View attachment 48363
If we use 20½k as v0 for the ship’s speed after impact, 0.2k as v1 for the ship’s speed at dead stop and 9.8 as C interpolated from table 1 for Titanic deadweight, we found that SJ (the inertial stopping distance) equates 4.95 nautical miles.
If we then use Captain Topley empirical formula with the same data to corroborate ALE algorithm, while taking advantage of inserting the time it took for Titanic to stop as witnessed (11:45pm – 12:00pm), we found that SJ equates 5.0 nautical miles within a ¼ of an hour.
View attachment 48364
If we draw the result neatly on a nautical chart, making the vessel turning more rapidly at first to then equilibrate her lateral pressure forces and finally stabilize on a North heading by compass, the distance found from the wreck is 15.8 nautical miles, not the celebrated 13 nautical miles.
View attachment 48365
As I was reading Samuel’s book, I came across and froze to that sentence;
Senator SMITH; Mr. Boxhall, you seem to be the one upon whom we must rely to give the difference between ship's time and New York time; or, rather, to give ship's time and give the New York time when this accident occurred.
Mr. BOXHALL; At 11.46 p.m., ship's time, it was 10.13 Washington time, or New York time.
That very single reply is a very significant and reveling phrase! Like Samuel stated, it certainly played a role in the CQD miscalculations, since at 11.46p.m., ship's time, it was not 10:13pm New York time, but 09:44pm! Let’s see what I come up with…
«At 11.46 p.m., ship's time, it was 10.13 p.m. New York time»
In modern notation, at 23:46 LAT it was 22:13 NYT. Thence, 23:46 LAT – 22:13 NYT = 01h33 time difference between the liner and New York or 03h27 between the liner and Greenwich or 05h00 between New York and Greenwich.
When Boxhall made is famous calculations to deduce the CQD position, he used 23:46 LAT for the collision, 22:36 GMT as noted in his Celestial Navigation Logbook for the evening celestial fix and a speed of 22 knots.
1. Boxhaul Calculated Distance Run:
Collision Time:
23:46 LAT = 22:13 NYT
23:46 LAT – 22:13 NYT = 01h33
05h00 – 01h33 = 03h27 GMT
Running Time between the 22:36 GMT celestial fix and 03:27 GMT collision time:
[(24:00 – 22:36) + (03:27)] = 04h51
Distance Run:
04h51 x 22 knots = 106.7 nautical miles
2. True Distance Run:
23:46 – 02h02 = 21:44 NYT
23:46 + 02h58 = 02:44 GMT
Time elapsed between 23:46 LAT and 22:36 GMT celestial fix:
23:46 + 02h58 = 02:44 GMT
[(24:00 - 22:36) + 02:44] = 04h08
Distance Run:
04h08 x 22 knots = 90.9 nautical miles
Difference:
Boxhall 106.7 miscalculated miles - 90.9 true miles = 15.8 nautical miles
As I said previously; «If we draw the inertia stopping distance on a nautical chart, Boxhall CQD distance found from the wreck is 15.8 nautical miles.». Strange coincidence isn’t it?
Notes:
Astern power equates 40% Ahead power
Thomas P. Dillon;
engines brought to stop 1½ minute after impact
engines stop for ½ minute
engines brought to Slow Astern for 2 minutes
engines stop
engines brought Ahead for 2 minutes
engines Stop for good
Engines brought Ahead for 2 minutes supersedes engines brought Slow Astern for 2 minutes.
Case 2. Frederick Scott:
engines brought to stop 1½ minute after impact
engines brought Astern for 5 minutes
engines Stop
engines brought Slow Ahead for 10 minutes
engines Stop for good
Engines brought Slow Ahead for 10 minutes supersedes engines brought Astern for 5 minutes.
Thence, the liner drifted mostly dead on her own inertia...
Astern power equates 40% Ahead power
x
Im just wondering where you get this
When running ahead at 83 revolutions per minute on her reciprocating engines, the entire power plant would develop about 59,000 horsepower, of which 18,000 horsepower would be contributed by the turbine. (Halpern)
So you shut off the turbine the Triple expansion engines develop 41000 HP
Titanic sea trials ""crash stop" was performed in which the engines were reversed full ahead to full astern, bringing her to a stop in 850 yards (780 m) or 3 minutes and 15 seconds."
So there was enough power to stop her in half a mile at 20 .5 knots including "reversal tiime" (but probably not response time )
.
For reversal time
With engineers at the ready, it would take from 10 to 20 seconds to get the engines to start backing and about 50 to 60 seconds for them to start backing hard. (SAM)
So its 60 second or more for full power and then stopped in 140 more seconds How does the square with 40 % power?