What firm evidence? The evidence on record is that the officers expected Titanic to reach the ice around 11pm if not sooner.

The evidence given by the 5th officer which you reject. I refer to the evidence which states that

*Titanic* covered a distance of 125.7 miles in 6 hours from Noon, giving an average of 20.95 knots over 6 hours.

I remind you of what 5th Officer Lowe stated under oath:

(1). "Her speed from noon until we turned the corner was just a fraction under 21 knots."
(2)

*"I used the speed for the position at 8 o'clock, and got it by dividing the distance from noon to the corner by the time that had elapsed from noon until the time we were at time corner."*
You should consider that Lowe describing how he obtained of an 8 pm DR.

Lowe was required to carry out 2 separate calculations to arrive at his 8 pm DR position.

Lowe was not on the bridge when

*Titani*c turned

*The Corner* at 5-50 pm that evening so he had no idea of how far she had run from Noon to that moment. He simply knew that the measured distance from the Noon position to the to the turning point was 126 nautical miles. In any event, he would most certainly not divide that number by 5 hours 50 minutes to obtain a DR for the turn position. To suggest he would is nonsense. he was trying to explain to a layperson how he worked.

Boxhall or Moody should have calculated a DR for 5-50 pm and noted it in the Scrap Log. This was standard practice on every British Merchant Vessel. It was usual to call the after bridge to obtain the Patent Log reading at the time of turn. However Boxhall did not use the patent Log...he used engine rpm.

However, on

*Titanic,* the patent Log was read every 2 hours. The 6 pm reading would be available for Lowe to use and the vidence shows that he did use the Patent Log. In fact 8 pm was the time that Lowe could be certain of a value for average speed to use in his calculations. He already knew the courses. His work would then consist as follows:

__Calculation A...DR for 5-50pm__
1. Divide 6 pm log reading by 6...average speed obtained: 20.95 Knots therefore log distance to 6 pm = 125.7 nautical miles.

2. Multiply 5 hours 50 minutes by 20.95 to obtain distance Noon to the moment of turn. (Hence

* evidence (1) *above).

3. To the Noon position, apply distance run on a course of 240.5 True to obtain the DR position of where

*Titanic* turned.

__Calculation B__
1. To the 5-50 pm DR position obtained from A run 2 hours and 10 minutes on a course of 265.5 True at an average speed of 20.95 knots. ( He used that average speed because as he told his questioner

*"If you take the average speed from 12 to 6 - that is giving her a run of six hours - she will not jump up in two hours, from 12 to 6 o'clock, from that average speed."*

This means that Lowe used a total distance of 8 x 20.95 knots = 167 miles from Noon until 8 pm to calculate his DR position for the end of his Watch.

if you accept the second Patent log reading taken at the time of impact, then

*Titanic* ran anothert 93 miles until impact. We know she averaged 22.5 knots during that last period in her working life therefore she would have steamed for another 4 hours 8 minutes unril she hit the iceberg, not 3 hours 40 minutes. She would have steamed for less time had she worked up to 22.5 knots between 7-30 pm sights and 8 pm.

However , the foregoing only works if you accept Lowe's patent log evidence. If you don't, then why do your accept QM Rowe's patent log evidence?