Alicia Coors
Guest
In a monograph published on the E-T site, Capt. L.M. Collins provides a meticulous cross-check of Fourth Officer Boxhall's arithmetic in computing Titanic's position when the ship began to sink. He demonstrates with egregious precision how a position of 41°46'N 50°14'W is calculated by dead-reckoning from her last position determined by stellar observation, 4h19m prior to the collision.
Dave Gittins suggests that Boxhall misread his Traverse Tables while crunching the numbers, and therefore the CQD position is suspect. I think there is a far simpler explanation.
The word "current" is not found in Duke's article at all; Dave mentions it exactly once (in the context of the 1990-92 computation, not his own).
A reasonable person would dispute the contention that Titanic drifted ~13 nm. from her presumed position at the moment of collision to the wreck site. If the distance/time equation is solved for ~13/~2, the current would have to be around 6 knots(!) This is unlikely the case. An explanation for the 13 miles must lie elsewhere.
Since Boxhall's computation apparently works if the current is ignored, I believe that the drift should be applied over the total time between the evening shoot and the sinking (an interval of 6h39m) giving an average velocity of a little less than 2kt.
Applied to the time between the celestial shoot and the collision, a drift of 8.5 nm at this rate would have occurred; from collision to wreck site, the remaining distance of 4.5nm would be traversed.
Titanic encountered her fate at 41°44'N 50°W.
Navigational Confirmation of Titanic's CQD Position
Explore why Titanic’s CQD distress position was accurate, despite a 13-mile drift to the wreck site, according to navigational analysis.
www.encyclopedia-titanica.org
Dave Gittins suggests that Boxhall misread his Traverse Tables while crunching the numbers, and therefore the CQD position is suspect. I think there is a far simpler explanation.
The word "current" is not found in Duke's article at all; Dave mentions it exactly once (in the context of the 1990-92 computation, not his own).
A reasonable person would dispute the contention that Titanic drifted ~13 nm. from her presumed position at the moment of collision to the wreck site. If the distance/time equation is solved for ~13/~2, the current would have to be around 6 knots(!) This is unlikely the case. An explanation for the 13 miles must lie elsewhere.
Since Boxhall's computation apparently works if the current is ignored, I believe that the drift should be applied over the total time between the evening shoot and the sinking (an interval of 6h39m) giving an average velocity of a little less than 2kt.
Applied to the time between the celestial shoot and the collision, a drift of 8.5 nm at this rate would have occurred; from collision to wreck site, the remaining distance of 4.5nm would be traversed.
Titanic encountered her fate at 41°44'N 50°W.