P
PeterChappell
Member
As we say in aviation circles, severe clear.
Can't say about Californian's masthead lights because I don't have specific information about them, but Titanic's masthead light seen at a distance of 15 miles would appear to be about as bright as the pole star Polaris, which is a star of magnitude 2 in the constellation Ursa Minor.
Presumably we can assume the Californian's (unsighted) stern light was much less bright to the Titanic's bridge, perhaps a tenth or even an hundredth that of the Titanic's masthead light to the Californian? That would be equivalent to stars of magnitude 4.5 and 7 respectively, since each magnitude change accounts for a change of 2.518 the brightness.
If the height of the stern light was at a similar height to Titanic's bridge at around 22 metres and at 15 NM distance, it would place it around 11 minutes of angle above the horizon as seen from the bridge. This is based on this formula from this 'beyond horizon' calculator. The horizon itself would be just a couple of minutes lower than the horizontal at the height of the Titanic's bridge.
This is how mast lights of 4.5 and 7 magnitude would appear against the background of stars in the general direction of the Californian, 7 minutes after the collision. These are labelled just above the horizon, indicated by the lower green line.
Notice how few stars are within this 2 degree band. This is due to the effect of light extinction, as the starlight passes through a greater mass of atmosphere near to the horizon. Also labelled is a normally bright 2.9 magnitude star reduced to 6.57, and a 3.74 magnitude star reduced to 6.48 magnitude due to these extinction effects.
There are no stars below 2 degrees of altitude/elevation brighter than the 5th magnitude after allowing for extinction. So a light of 4.5 magnitude (a tenth as bright as of Titanic's mast light) shouldn't be easily confused with the stars.
The 7th magnitude light (a hundredth as bright as Titanic's mast light) is more challenging, as there are 12 stars brighter than the 7th magnitude within 2 degrees of the horizon at that time. Ideally a planisphere would have been useful to identify the stars on the horizon, as these would be be printed as 3rd and 4th magnitude objects.
The gradually increasing angle of the ship would make the position of the horizon more difficult to determine, although the abundance of stars above a certain elevation would act as a guide. Note also that mast lights would also be affected by extinction to some extent, so I'm unsure if that is allowed in Sam's calculations.
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